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Mathematics 9 Online
OpenStudy (anonymous):

sin-1(sin 2pi/3)

OpenStudy (mertsj):

\[\sin \frac{2\pi}{3}=\frac{\sqrt{3}}{2}\]

OpenStudy (mertsj):

Now...inverse sine values must be between -pi/2 and pi/2. So your job is to find the angle within that range whose sine is sqrt3/2

OpenStudy (anonymous):

2e-13

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