algebra 1anyone?
perform the operation indicated.

square root of twelve +3 square root of 75 - 2 and the square root of 27.

Question

algebra 1anyone?
perform the operation indicated.

square root of twelve +3 square root of 75 - 2 and the square root of 27.

anonymous · Answer

$$\sqrt{12} +3\sqrt{75} - 2\sqrt{27}$$

anonymous · Answer

√4√3+3(√25)√(3)-2(√9)√3= 2√3+15√3-18√3=-√3 i hope this is the awsner

anonymous · Answer

my book says the answer is something like :$$ax \sqrt{11a}$$

anonymous · Answer

any thought of how to get it?
@cmath1917

anonymous · Answer

ok take 4 out of √12 25 out of √3√75 and 9 out of 2√27
then the naturals become 2 5 and 3 respectively 
then simplify 2√3+3*5√3-2*3√3=11√3 i have changed my last incorrect  of -√3