Question

Help! I need to show work for this question.
12b^-2-7b^-1+1=0

Answer 1

I got b = 4,3

Answer 2

\[\frac{ 12 }{ b^{2} }-\frac{ 7 }{ b }+1=0\]
Multiply both sides by b^2
\[b^{2}-7b+12=0\]
So your answer looks right.