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\[8\frac{ 1 }{ 6 } = \frac{ 49 }{ 6 }\]\[4\frac{ 2 }{ 3 } = \frac{ 14 }{ 3}\]\[\frac{ 49 }{ 6 } / \frac{ 14 }{ 3 }= \frac{ 49 }{ 6 } * \frac{ 3}{ 14 }\]\[= \frac{ 49(3) }{ 6(14) } = \frac{ 147 }{ 84 } = \frac{ 7 }{ 4 }\]
The answer is D. \[\frac{ 7 }{ 4 } = 1\frac{ 3 }{ 4 }\]
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