Question

Finally , I solve is true or Not?
http://i.imgur.com/q72VWup.jpg
Pleaaaaaase I need it Before school time
It's only 3 hours
Please .. Please

Answer 1

Now for (6) so what ? True or not ?
I just need yes and no 😰😥
Please

Answer 2

http://i.imgur.com/3ig1SRT.jpg (6)

Answer 3

It is hard to read your answer
what did you get for the inverse of A ?

Answer 4

A inverse
0 , 1, 2
-1, 3, 0
1, -2, 1

Answer 5

Sorry for my bad writing

Answer 6

yes that looks good for A inverse
now multiply A inverse times the vector [2 0 2] transposed

I think you get [4 -2 4]^T

Answer 7

I get (4, -2, 0) but yes it (4,-2,4) sorry my fault

Answer 8

A is
-3 5 6
-1 2 2
1 -1 -1

A transpose is

-3 -1 1
5 2 -1
6 2 -1


the inverse of A transpose
0 -1 1
1 3 -2
2 0 1

which is the same as the transpose of A inverse

Answer 9

Ok, can you help me for (6) my answer it is T or F ?
I do it 3 matrix for A , A transpose & A transpose inverse

Answer 10

question 6 is A^T * x = b
where x means the vector [ x y z]^T

the inverse of A^T (A transpose) is the transpose of A inverse
so take the transpose of A inverse from question 1, and multiply it times [1 -1 2]^T

Answer 11

Yes I know about transpose and inverse but in Q (6) what i should I do ?

Answer 12

multiply out inv(A^T) * [1 -1 2]^T

Answer 13

you should get
3
-6
4

Answer 14

This means
X=3
Y=-4
Z=5

Answer 15

Where your X,y&z came ?!
I questioned in my solution