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Find the value of v in each equation. v=log(10)1000
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you are being asked to solve \[10^y=100\]
Well, 10^y=1000, but basically yes.
oops
I still don't understand.
log base ten asks what power 10 must be raised to in order to get a number. Log(10) of 10, for example, is one. One simple way to do logs in base ten is to count the place of the highest-place digit. The log base 10 will always be between that number of places and one more, depending on the number itself: 525 has a higher log than 216, but both are between two and three.
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Thank you!
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Yes
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