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Determine g-1(x) of the function g(x) = 1 /(2x + 6) where x≠ -3. please help!!!!
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put \[y=\frac{1}{2x+6}\]then switch \(x\) and \(y\) because that is what the inverse function does, and get \[x=\frac{1}{2y+6}\] then solve for \(y\)
\[x=\frac{1}{2y+6}\] \[x(2y+6)=1\] \[2xy+x=1\] \[2xy=x+1\] \[y=\frac{x+1}{2x}\]
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