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Algebra
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Write an exponential function y = abx for a graph that includes (1, 15) and (0, 6).
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\[y=ab^x\] if \(x=0\) you ge t \[6=ab^0=a\times 1=a\]telling you \(a=6\)
y = ab^x , so using the point (x,y) = (0,6) --> 6 = ab^0 ; b^0 = 1 so 6 = a(1) . Therefore, a = 6 Using the second point (1, 15) and the fact that a = 6 --> 15 = (6)b^1 or 15 = 6b Therefore, 15/6 = b (or 5/2 = b, when you reduce the fraction) Finally, substituting 6 for a and 5/2 for b, into the general equation y = ab^x gives: y = 6(5/2)^x So that is the answer. :)
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