Question

Find the perimeter of each of the two noncongruent triangles where a=15 b=20 A=29

Answer 1

Law of sines to find possible B values:
\[\frac{ Sin(A) }{ a } = \frac{ Sin(B) }{ b }\]
Then, using these two B values you can find the two possible C values
\[A° + B° + C° = 180°\]
And the law of cosines to find the length of c:
\[c^2 = a^2 + b^2 -2(ab)\cos(C)\]