Question

(sqrt8 + sqrt12)^2 + (sqrt8 - sqrt12)^2 = c^2

Answer 1

c is hypotenuse.
its a triangle question.

Answer 2

FOIL

Answer 3

Damn forget I said anything

Answer 4

really.

Answer 5

...
i know i have to foil it and then simplify
like write each set of parenthesis twice
so after writing all that out
can i do

(sqrt64+sqrt96+sqrt96+sqrt144)+(sqrt64-sqrt96-sqrt96+sqrt144)

or is that wrong.

Answer 6

\[\left(2 \sqrt{2}+2 \sqrt{3}\right)^2+\left(2 \sqrt{2}-2 \sqrt{3}\right)^2=c^2 \]\[c^2=40 \]\[c=2 \sqrt{10},c=-2 \sqrt{10} \]

Answer 7

thank you.