Question

let z= √3-i and w=-2-2i

convert z and w to polar form

Answer 1

if you understood how to find th emodulus and arguement; the polar form is just:\[\mod~(cos(\arg)+i~sin(\arg))\]

Answer 2

o ok

Answer 3

if youre still not sure how to work the mod and arg, im willing to walk thru one of them with you

Answer 4

im ok now

Answer 5

good luck :)