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Algebra 16 Online
OpenStudy (anonymous):

Solve. x2 + 4x – 4 = 0

OpenStudy (anonymous):

x=-2

OpenStudy (anonymous):

(x+2)^2=0

OpenStudy (anonymous):

thats not an answer choice :(

OpenStudy (anonymous):

well then...

OpenStudy (anonymous):

they all have a square root equation

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

Oh ok i can help i think i'll brb ok 2@gyse94

OpenStudy (anonymous):

\[x=\frac{ -2\pm \sqrt{{16}} }{ 2 }\]

OpenStudy (anonymous):

oh did u already find the answer?

OpenStudy (anonymous):

that is one of the answer choices no not yet

OpenStudy (anonymous):

but that one is an option

OpenStudy (anonymous):

is this an option x=-2+2squareroot2? Sorry but i cant find the squareroot symbol on my computer

OpenStudy (anonymous):

or wat about this is this an option -2-2squareroot2?

OpenStudy (anonymous):

yes. how did you get that?

OpenStudy (anonymous):

i think @Muj_14 is correct @gyse94

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

thank you!!!

OpenStudy (anonymous):

You're welcome!

OpenStudy (anonymous):

\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\] \[x=\frac{ 4\pm \sqrt{16+16} }{ 2 }\] \[x=\frac{ 4\pm4\sqrt{2} }{ 2 }\] \[x=2\pm2\sqrt{2}\]

OpenStudy (anonymous):

:)

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