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OpenStudy (anonymous):
help.. f(x)=4x+1 and g(x)=x^2+1 find (f 0 g)(x)
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OpenStudy (espex):
Is that representing the dot product? What is the 0 in-between the f&g?
OpenStudy (anonymous):
is( f o g) not actually the 0
OpenStudy (espex):
So f(g(x))
OpenStudy (anonymous):
correct
OpenStudy (espex):
Which just means that you take 'g' and plug it into 'x' inside 'f'.
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OpenStudy (anonymous):
yes, but th I dont get the final answer correctly
OpenStudy (espex):
Let's see how you're setting it up and discover where you went wrong.
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