Question

HELP PLZ
Complete the following:
(a) Use the Leading Coefficient Test to determine the graph's end behavior.
(b) Find the x-intercepts. State whether the graph crosses the x-axis or touches the x-axis and turns around at each intercept.
(c) Find the y-intercept.

f(x) = x2(x + 2)

Answer 1

The leading coefficient is positive and thus the graph goes to positive infinity as x-> inf

The x intercepts are the roots, so 0 with multiplicity 2 and -2 with multiplicity 1 thus it touches at 0 and goes through at -2

Answer 2

the y intercept is the value you get when x=0, thus the y-intercept is 0

Answer 3

hmmm

Answer 4

As the leading coefficient has order 3 (odd) then the graph falls to the left and rises to the right.

Answer 5

ok, what part of what @ceb105 said confused you?

I mean, we're assuming you've covered this in class already and your textbook has at least one chapter with it

Answer 6

as opposed to you asking @ceb105 to "write it for you"

Answer 7

but if you need clearing out, sure :)

Answer 8

I was saying how do i answer it.
A is
B is
C is for ex

Answer 9

well, A was already answered by @ceb105
B you'd need to find it by settting y=0
C you'd need to find it by setting x=0

Answer 10

A is The leading coefficient is positive and thus the graph goes to positive infinity as x-> inf

Answer 11

yes

Answer 12

oh okay

Answer 13

is this B it touches at 0 and goes through at -2

Answer 14

yep

Answer 15

ok so c is?

Answer 16

set x to 0

Answer 17

is it 2 idk

Answer 18

yes

Answer 19

the graph is more or less like so