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How would I prove 2/2^n = 1/2^n-1
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\[\begin{align*}\frac{2}{2^n}&=\frac{1}{2^{n-1}}\\ \frac{2^1}{2^n}&=\cdots\\ 2^{1-n}&=\cdots\\ \frac{1}{2^{-(1-n)}}&=\cdots\\ \frac{1}{2^{n-1}}&=\cdots \end{align*}\]
or in other words...you reduce the fraction by a factor of 2 just like 2/4 = 1/2
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