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Find the inclination, theta, of the line passing through the points (5,0) and (-5,5)
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could someone tell me the equation to use?
Inclination is actually the slope which is \[\tan \theta \] So find the slope first using the points given. Slope = \[\frac{ y _{2} - y _{1}}{ x _{2} - x _{1} }\]
Can you find the slope?
it is -.5
yes
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now \[\tan \theta = -0.5\] So \[\theta = \tan^{-1} (-0.5)\] use calculator to find it
it gives me - 26.6
i have the choices of 26.6, 153.4, 63.4, 116.6 or none of these
and so would it 26.6 ?
oh. okay! Thank you!
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My earlier answer is right bad teacher. it is 153.4 and that is final
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