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Mathematics 21 Online
OpenStudy (anonymous):

how many different "words" can be created by RUBBERBAND I know it's 10!/2!3! but can someone explain why

OpenStudy (bahrom7893):

so you want all the possible permutations of the letters. Which is 10! But since you have R repeated twice and B repeated 3 times, you need to divide that 10! by 2!*3!

geerky42 (geerky42):

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