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Mathematics 6 Online
OpenStudy (anonymous):

What is the equation of the following graph? Answers: x-4=1/12(y-3)2 y-4=1/12(x-3)2 y-4=1/12(x+3)2 x+4=1/12(y+3)2

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

since it is facing horizontal, it must of form x-h = a(y-k)^2

ganeshie8 (ganeshie8):

so we can strike off middle two options right away

OpenStudy (anonymous):

ok so then would the answer happen to be the first one?

ganeshie8 (ganeshie8):

let me think i didnt do conics recently

OpenStudy (anonymous):

This is Parabolas

ganeshie8 (ganeshie8):

parabola is a conic

ganeshie8 (ganeshie8):

ok, since the vertex is at (4, 3), h = 4, k = 3

ganeshie8 (ganeshie8):

plug them in the above equation x-h = a(y-k)^2 x-4 = a(y-3)^2

ganeshie8 (ganeshie8):

so you're right its A !

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