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Please help! Simplify: 4x-32y divided by 4
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factor out the 4 from the numerator. You get \(\huge \frac{4(x+8y)}{4}\)
Remember: \(\large \frac{4}{4}=1\)
Shouldn't that be \[\frac{ 4(x-8y) }{ 4 }\].
yes!
lol
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It's the same thing!
But nt e signXD
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