Question

X^2+6x=7
Can someone explain this? And find a,b, and c?

Answer 1

x^2+6x-7=0
x^2-x+7x-7=0
x(x-1)+7(x-1)=0
(x+7)(x-1)=0
x=-7,x=1

Answer 2

I'm just having a bit of a hard time understanding the third step, is there any sort of explanation?

Answer 3

i just take x common

Answer 4

one is x square and another is x so you can takke x common from each other

Answer 5

himalya thinks you are trying to solve for x, as opposed to determining the specific coefficients of the standard:

ax^2 + bx + c