Question

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = 3x^2 – 12x + 12

A. 1 point in common; vertex on x-axis

B. 2 points in common; vertex below x-axis

C. 2 points in common; vertex above x-axis

D. no points in common; vertex above x-axis

Answer 1

start with finding \(b^2-4ac\)

Answer 2

somebody said it ws D so i just wanna see if there right

Answer 3

3x^2 – 12x + 12
^ ^ ^
a b c

Answer 4

b?

Answer 5

how

Answer 6

my sistr said

Answer 7

its not b

Answer 8

lets find it step by step

Answer 9

what do you get for \(b^2 - 4ac\) ?

Answer 10

ohh nevermind i found it out its C

Answer 11

its not C either

Answer 12

lets go step by step ok

Answer 13

ohh i mean A i was looking at A ten i looked @ c

Answer 14

lol A is correct.