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b. Find the angle A for the triangle ABC given that: AB = 14mm BC = 29mm B = 90° Has to be done using trigonometric functions
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What formula do I use?
Taking BC as the perpendicular and AB as the base; \[\tan \theta =\frac{ perpedicular }{ base }\] \[\tan \theta= \frac{ 29 }{ 14 }\]
I got 64.23 degrees (2dp) as my final answer.
Yep. Correct.
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