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Precalculus
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if f(x)=2x, g(x)= 2x-1, and h(x)= square root of x, find (fogoh)(9)
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\[h(x)=\sqrt{x}\] \[h(9)=\sqrt{9}= 3\]
Now you replace x=3 in g(x). \[g(x)=2x-1\] \[g(3)= 2(3)-1= 5\]
Finally, replace x=5 in f(x) \[f(x)=2x\] \[f(5)= 2(5)= 10\]
oh okay! i see... so do i then multiply them together? or add them?
No. 10 is the answer. Actually, did them separately for you. Otherwise, it's like this: \[f(g(h(x)))= 2[2\sqrt{9}-1]\]
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But you get the same answer i.e. 10.
oh okay!! thank you so much!!!!
yw! :)
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