If AB are 28 m.u. apart, what percent of the progeny from selfing the heterozygote AB/ab would be Ab/ab?

Question

abb0t · Answer

I know it should be 5.04%, but I don't understand clearly how they got that.

thomaster · Answer

Damn i did a lot of genetics courses but the map units thing was never in it, which is too bad :( I like genetics stuff

abb0t · Answer

@nincompoop

nincompoop · Answer

you calculate the 28% of 36% then divide that by 2

in your punnet you have a chance 36% of getting ab |dw:1368728986013:dw|

abb0t · Answer

how did you get 36%? Lol.

abb0t · Answer

ohh did u just subtract from 100%??

abb0t · Answer

and divided by 2? i think im seeing what u did there.

nincompoop · Answer

ya! lol

abb0t · Answer

and how did they get 5.04%? Lol

abb0t · Answer

oh wait nvm, i think i see it. 
since it was 28, each is 14 right? 
oh oh OHHH SHIET!!
OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH SHIET!!!

I THINK I GOT THIS!!

abb0t · Answer

|dw:1368729288883:dw|