Question

What is this function written in intercept form?
y=-x^2-x+6

A. y=-(x+2)(x+6)
B. y=-(x+2)(x-6)
C. y=(-x+3)(x-4)
D. y=-(x-2)(x+3)

Answer 1

\(y = -(x^2 + x - 6)\)

you want (x^2 + x - 6) to be in the form (x + a)(x + b), expanding the last one:
(x + a)(x + b) = x^2 + (a + b)x + ab

So what you want to do is find 2 numbers a and b so that a + b = 1, and a * b = -6 then
y= -(x +a)(x + b)

Answer 2

oh okay i see.... so woud it be -2 and 3?

Answer 3

Yes :)

Answer 4

so d?!

Answer 5

yep

Answer 6

thank you so much!