Question

What is the inverse of h?

h(x) = 6x + 1

Answer 1

\(h\) says
a) multiply by 6
b) add 1

inverse says
a) subtract 1
b) divide by 6
\[h^{-1}(x)=\frac{x-1}{6}\]

Answer 2

like if you were solving
\[6x+1=17\] you would
a) subtract 1
b) divide by 6
\[6x+1=17\]
\[x=\frac{17-1}{6}\]

Answer 3

umm this isnt one of the multiple choice answers