Question

Explain how to find the equation for the quadratic function that has its vertex at (-1,2) and contains the point (0,-1)

Answer 1

using vertex form, y = a(x – h)^2 + k, where (h,k) is the vertex, y = a(x+1)^2 + 2, and then solve for the point (0,-1)

Answer 2

Thank you