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OpenStudy (anonymous):
Write a formula for the nth term of the following geometric sequence. -3, 3/5, -3/25, 3/125,... abase(n)=____*(______)^(n-1)
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OpenStudy (anonymous):
|dw:1368761889507:dw| the equation would be -3 * (-1/5)^(n-1)
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