Question

Can Someone Help me Answer This Please

Quadratic Equation in One Variable

Solve By Factoring

1.4x^2-36=0
2.7x^2+19x=6
3.8x^2+14=-5
4.x^2+8x-9=0

Solve By Quadratic Formula

5.3x^2-2x=8

Solve By Completing Squares

6.x^2-3x-4=0

Answer 1

http://www.youtube.com/watch?v=eF6zYNzlZKQ
watch plz! factoring teacher

Answer 2

1. 4x^2-36=0
collect like terms
4x^2=36,(2x)^2=6^2
find the sqareroot on both sides
you get 2x=+or- 6
x=-3,x=3

Answer 3

do number 3 that same way
number 2 and 4,well find the factors

Answer 4

i slept, sorry my answer in 4

x^2+8x-9=0
(x+9)(x-1)=0
x+9=0 x-1=0

x=9 x=-1

Answer 5

Are your questions graded?

Answer 6

ye

Answer 7

You are not allowed to post graded questions on openstudy, its against the CoC, because it is considered cheating.
http://openstudy.com/code-of-conduct

Answer 8

1.(2x)^2-6^2=(2x+6)*(2x-6) so x=+3,-3 use formula a^2-b^2=(a+b)*(a-b)

2.7x^2+19x-6=0 thn 7x^2+21x-2x-6=0 so x=-3,2/7

4.x^2+9x-x-9=0 thn x(x+9)-1(x+9)=0 so x=-9,1
5.3x^2-2x-8=0 thn use sqt(-2)^2-4*3*8/2*3 so (SQT100)/6 so +10/6 or -10/6