Hi everyone! I have posted my work as 36.bmp Please help me finish solving this quadratic formula...Thanks! :o)

Question

anonymous · Answer

attachment

anonymous · Answer

I need the final answer to be 6/2-3sin(theta)

anonymous · Answer

To be honest, I'm not even sure if i'm doing this correctly

anonymous · Answer

and let me rephrase...I THINK the final answer needs to 6/2-3sin(theta) but I'm not even sure about that anymore because the numbers don't match my work on the calculator

anonymous · Answer

I have to go to bed but please post whatever help or advice you can give...I will look at it in a few hours! Thanks everyone!

phi · Answer

you can write the bottom as
$$ 8 \cos^2 -8 \sin^2 - 2\sin^2 \ 8(\cos^2 - \sin^2)- 2\sin^2 \ 8(1-2\sin^2) - 2 \sin^2$$

using the identity cos^2 - sin^2 = 1-2sin^2

simplify, factor a sum of squares, and cancel terms
you get
6/(2-3sin)