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Precalculus 16 Online
OpenStudy (anonymous):

what is the magnitude and direction of the vectors (3,4). i don't know how to find the direction... i need help

OpenStudy (ajprincess):

\[magnitude=\sqrt{x^2+y^2}\] \[direction=tan^{-1}(\frac{y}{x})\] here x=3 and y=4. Does that help? @nasrally

OpenStudy (anonymous):

yeah i guess.. i,m gonna try doing it right now.. thanks by the way

OpenStudy (ajprincess):

k take ur time nd welcome:)

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