Question

Solve. (x + 2)^2 = 1

Answer 1

completing the square

Answer 2

take square root both sides
\(\sqrt{(x+2)^2}=\pm\sqrt{1^2}\)
\(x+2=~or~x+2=-1\)

Answer 3

(x+2)^2=1
x^2+4x+4=1
x^2+4x+3=0
x^2+x+3x+3=0
x(x+1)+3(x+1)=0
(x+1)(x+3)=0
So, x=-1 or x= -3

Answer 4

*
x+2=1 or x+2=-1

Answer 5

x=1 or x=-1 ?

Answer 6

x+2=1
x=1-2
=-1
x+2=-1
x=-2-1=?