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OpenStudy (anonymous):
factor the trinomial 8c^2-96c+160
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OpenStudy (anonymous):
If im not wrong I think it's 8(c-10)(c-2)?
OpenStudy (campbell_st):
take 8 out as a common factor \[8(c^2 -12c + 20)\] find the factors of 20 that add to -12... they are both negative... then you will have 8(c + factor 1)(c + factor 2) good luck
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