Question

I'm so lost on this question
factor the trinomial 15b^2-22bc-5c^2?

Answer 1

I'm thinking you're missing something there, recheck your polynomial

Answer 2

yeah it was a term missing
15b^2-22bc-5c^2

Answer 3

recheck it again :)

Answer 4

factor the trinomial
15b^2-22bc-5c^2

Answer 5

I see nothing there but just grouping, which isn't much of a factoring :|

Answer 6

the negativity of the last term pretty much cancels it out as a perfect square, so :|

Answer 7

15*-5=-75
25-3=22
25*-3=-75
\[15b ^{2}-22bc-5c ^{2}=15b ^{2}-\left( 25-3 \right)bc-5c ^{2}\]
\[=15b ^{2}-25bc+3bc-5c ^{2}=5b \left( 3b-5c \right)+c \left( 3b-5c \right)=\left( 3b-5c \right)\left( 5b+c \right)\]