find the solutions of the system.
1. y = x² + 3x – 4
y = 2x + 2 (1 point)
(–3, 6) and (2, –4)
(–3, –4) and (2, 6)
(–3, –4) and (–2, –2)
no solution

2. y = x² – 2x – 2
y = 4x + 5 (1 point)
(–1, 1) and (–7, –23)
(–1, 1) and (7, 33)
(–1, 33) and (7, 1)
no solution

Question

find the solutions of the system.
1. y = x² + 3x – 4
y = 2x + 2 (1 point)
(–3, 6) and (2, –4)
(–3, –4) and (2, 6)
(–3, –4) and (–2, –2)
no solution

2. y = x² – 2x – 2
y = 4x + 5 (1 point)
(–1, 1) and (–7, –23)
(–1, 1) and (7, 33)
(–1, 33) and (7, 1)
no solution

mertsj · Answer

Since you have the answers, it is probably simplest to plug the points into the two equations and see which ones make both equations true.