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Mathematics 15 Online
OpenStudy (anonymous):

ok

OpenStudy (campbell_st):

take 3 out as a common factor and you are left with \[3(x^2 + 4x - 12)\] makes it easier to factor the quadratic... 2 factors of 12 that add to 4... the smaller factor is negative.

OpenStudy (campbell_st):

nope try factoring using 6 and -2

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