Question

15x+32y=40, x+y=10, find xy please anser this

Answer 1

u mean x and y seperatly right

Answer 2

no the question sent to me was exactly as I wrote.

Answer 3

I guess the answer should be value of x and value of y multiplied??

Answer 4

there is no mean if together

Answer 5

x=280/17 , y=-110/17
xy=-30800/289

Answer 6

then i must be x and y seperately, I was givin this equation by my nephew.

Answer 7

is it possible to show me how you solve it. tks

Answer 8

x=10-y

15(10-y)+32y=40

17y=-90
y=-90/17

x=15.29

xy=-80.968

Answer 9

x+32\15y=40\32 15\32x +y=40\32

x+y=10 x+y=10

so y=32\15 Y +Y=10\32 -10 x=15\32 X+X=10\32 -10

Answer 10

x=10-y

15(10-y)+32y=40

17y=-110
y=-110/17

x=10-(-110/17)
x=280/17

xy=280/17*-110/17 = -30800/17

Answer 11

tks all for the help, really really appreciated.

Answer 12

x + y = 10 --> x = 10 - y
now sub 10 - y in for x in the other equation
15x + 32y = 40
15(10 - y) + 32y = 40 (distribute the 15 through the parenthesis)
150 - 15y + 32y = 40 (combine like terms)
150 + 17y = 40
17y = 40 - 150
17y = -110
y = -110/17
now sub -110/17 in for y
x + y = 10
x - 110/17 = 10
x = 10 + 110/17
x = 170/17 + 110/17
x = 280/17
check...
x + y = 10
280/17 - 110/17 = 10
170/17 = 10
10 = 10 (correct)
x = 280/17 and y = -110/17
xy = 280/17 * -110/17
xy = - 30800/17 = - 1811 13/17 or - 1811.76