Question

Find the root that is a real number.

Answer 1

\[\sqrt[3]{{-125}}\]

Answer 2

review comlex numbers

Answer 3

r= 5 , Theta= pi , n=3 , K=0,1,2
then \[\sqrt[3]{r} (\cos \frac{ 2k \pi+\theta }{ n ) +i \sin \frac{ 2k \pi+\theta }{ n } ) \]
so,

\[\[\sqrt[3]{r} (\cos \frac{ 2k \pi+\pi }{ n } ) +i \sin \frac{ 2k \pi+\pi }{ n} ) \]


k=0 : w0=1.71
k=1 : \[\sqrt[3]{5} (\cos \frac{ 2*1 \pi+\pi }{ 3 } ) +i \sin \frac{ 2*1 \pi+\pi }{ 3} ) \]w1= 1.71+0.09i

k=2 : w2: 1.70+0.16

Answer 4

OR REAL PART = -5.00

Answer 5

It was -5