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The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method. A. -2 and -4 B. -2 and 4 C. 2 and -4 D. 2 and 4
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5x + 2y = 18 3x - 7y = -22
right rad
actually, if the choices the given u can use the trials error can u check for the last one, woulde be the solution or not ?
what would it be?
let's check it (if it is D, 2 and 4) for the 1st equation : 5x+2y=18 5(2) + 2(4) = 18 10 + 8 = 18 RIGHT
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for the 2nd equ. 3x-7y=-22 3(2)-7(4)=-22 6-28=-22 RIGHT TOO :)
so, it is D
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