Question

Which of the following is equivalent to 7 sigma n=4 -2n+3

Answer 1

\[\sum_{n=4}^{7} -2n+3\]

Answer 2

make an attempt

Answer 3

–32

–27

–21

–8

Answer 4

make an attempt

Answer 5

1^2+3 2^2+3 3^2+3 4^2+3 5^2+3 6^2+3 7^2+3

Answer 6

all added together

Answer 7

no, it's -2(n) +3 ? so just multiply each by -2 and add 3

Answer 8

wait what?

Answer 9

so [1(-2)+3]+2(-2)+3 etc.?

Answer 10

yeah.............

Answer 11

ok so 1[(-2)+3]+[2(-2)+3]+[3(-2)+3]+[4(-2)+3]+[5(-2)+3]+[6(-2)+3]+[7(-2)+3]

Answer 12

(-2+3)+(-4+3)+(-6+3)+(-8+3)+(-10+3)+(-12+3)+(-14+3)

Answer 13

1+-1+-3+-5+-7+-9+-11

Answer 14

you have to start from 4 and end at 7. You started from 1

Answer 15

oh my bad

Answer 16

[4(-2)+3]+[5(-2)+3]+[6(-2)+3]+[7(-2)+3]
-8+3 -10+3 -12+3 -14+3
-5 -7 -9 -11
-32

Answer 17

THANKS SO MUCH!

Answer 18

you're welcome.