Question

Find the difference.
(2x3-5x2+3x-4)-(6x3-7x2-3x+3)
Simplify answer.

Answer 1

first you multiply with the negative sign
ditribute
- ( stuff in here )

Answer 2

then combine like terms

Answer 3

distribute*

Answer 4

Uggg those are suppose to be exponents

Answer 5

still its only combining like terms
same thing no difference

Answer 6

just distribute

- ( stuff in here)
^____|
multiply

Answer 7

then combine like terms

Answer 8

\[(2x^3-5x^2+3x-4)-(6x^3-7x^2-3x+3)\]
\[2x^3-5x^2+3x-4-6x^3+7x^2+3x-3\]

Answer 9

\[2x^3-6x^3-5x^2+7x^2+3x+3x-4-3\]

Answer 10

\[-4x^3+2x^2+6x-7

Answer 11

-4x^3+2x^2+6x-7

Answer 12

whatever works for you