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Calculus1 20 Online
OpenStudy (anonymous):

how do i proceed with integral \[(x^2+2)^{-3/2} dx?\]?

OpenStudy (raden):

let u = sqrt(2)tanθ

OpenStudy (raden):

du = sqrt(2) sec^2 θ dθ see ur integral becomes |dw:1368949571906:dw|

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