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solve (4 + 3i)2
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Distributive property !
a(b+c)=ab+ac
16+9i
7+24i
Erm \[(4 + 3i)^2?\]
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is that to the second power, or times two?
second power
16+24i-9
kinda lost
Multiply it like (4 + 3i) X (4 + 3i)
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\[4 \times 4+ 4 \times 3i+ 3i \times 4+3i \times 3i=......\]
Can you do it now ?
7+24i
8+6i
not a answer
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yep :)
8+6i IS your answer
7+24i is the right answer
How do you get 7+24i? @AravindG
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