Question

I need quick help on this question please (:

Answer 1

Satellite :D

Answer 2

find the third side via pythagoras, then take the appropriate ratios

Answer 3

it must be between 3and 7 right?

Answer 4

1+cos(t)^2=1/tan(t)^2 = sec(t)^2; sin(t)^2+cos(t)^2=1; or tan=sin/cos ; csc(t)=1/sin(t);

Answer 5

it is
\[\sqrt{5^2-2^2}=\sqrt{25-4}=\sqrt{21}\]