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Mathematics 13 Online
OpenStudy (anonymous):

PLEASE HELP! WILL MEDAL! Consider the following recurrence relation. See screenshot please :)

OpenStudy (anonymous):

OpenStudy (amistre64):

were are you lost in this at?

OpenStudy (anonymous):

all of it :(

OpenStudy (amistre64):

the first line is just plugging in n=0 into that f(n) and showing the Q(0) = f(0) = 4

OpenStudy (amistre64):

the next part is the induction step, assuming its true for some n=k Q(k) = 2 Q(k+1) + 3, but for some reason they dont what a k+1 in there yet so they shift the index to k-1 Q(k-1) = 2 Q(k) + 3

OpenStudy (amistre64):

pfft, -3 on the ends of those that is

OpenStudy (anonymous):

OpenStudy (anonymous):

@terenzreignz

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