Mathematics
12 Online
OpenStudy (boobear7411):
Help me ?
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OpenStudy (boobear7411):
ganeshie8 (ganeshie8):
hint : 10 = 2 * 5
ganeshie8 (ganeshie8):
hint2 : \(5 = \sqrt{5^2} = \sqrt{25}\)
OpenStudy (boobear7411):
Would it be 5 ?
ganeshie8 (ganeshie8):
5 is outside, but x is inside radical
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OpenStudy (boobear7411):
So 25 ?
ganeshie8 (ganeshie8):
so when you take 5 into the radical, it becomes \(5^2 = 25\)
ganeshie8 (ganeshie8):
Yes. \(x = 25\)
OpenStudy (boobear7411):
So the aswer is 25 ?
OpenStudy (boobear7411):
Could you help me with another one ?
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ganeshie8 (ganeshie8):
Yep
ganeshie8 (ganeshie8):
sure
OpenStudy (boobear7411):
ganeshie8 (ganeshie8):
\(\large \sqrt{4m} + 5\)
\(\large \sqrt{4 * 36} + 5\)
\(\large \sqrt{2^2 * 6^2} + 5\)
OpenStudy (boobear7411):
i am so confused
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ganeshie8 (ganeshie8):
you need to put m = 36, in hte given expression and simplify
ganeshie8 (ganeshie8):
are you clear upto 2nd step above ?
OpenStudy (boobear7411):
yes
OpenStudy (boobear7411):
oh i get it now how you did the 2 thingy and the 6 thingy
ganeshie8 (ganeshie8):
lol yes, 2 thingy squared gives the 4 thingy
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ganeshie8 (ganeshie8):
6 thingy squared gives the 36 thingy
;)
ganeshie8 (ganeshie8):
lets move on
ganeshie8 (ganeshie8):
square and radical cancel out
OpenStudy (boobear7411):
lol youre funny ♥
ganeshie8 (ganeshie8):
\(\large \sqrt{4m} + 5\)
\(\large \sqrt{4 * 36} + 5\)
\(\large \sqrt{2^2 * 6^2} + 5\)
\(\large 2 * 6 + 5\)
\(\large 2 * 6 + 5\)
\(\large 12 + 5\)
?
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OpenStudy (boobear7411):
17 ?
ganeshie8 (ganeshie8):
Yes !
OpenStudy (boobear7411):
thats the answer?
ganeshie8 (ganeshie8):
yes 17 is the answer. evaluate means, just finding the final value of the given expression.
OpenStudy (boobear7411):
Thank you ♥
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ganeshie8 (ganeshie8):
u welcome =)