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Mathematics 12 Online
OpenStudy (boobear7411):

Help me ?

OpenStudy (boobear7411):

ganeshie8 (ganeshie8):

hint : 10 = 2 * 5

ganeshie8 (ganeshie8):

hint2 : \(5 = \sqrt{5^2} = \sqrt{25}\)

OpenStudy (boobear7411):

Would it be 5 ?

ganeshie8 (ganeshie8):

5 is outside, but x is inside radical

OpenStudy (boobear7411):

So 25 ?

ganeshie8 (ganeshie8):

so when you take 5 into the radical, it becomes \(5^2 = 25\)

ganeshie8 (ganeshie8):

Yes. \(x = 25\)

OpenStudy (boobear7411):

So the aswer is 25 ?

OpenStudy (boobear7411):

Could you help me with another one ?

ganeshie8 (ganeshie8):

Yep

ganeshie8 (ganeshie8):

sure

OpenStudy (boobear7411):

ganeshie8 (ganeshie8):

\(\large \sqrt{4m} + 5\) \(\large \sqrt{4 * 36} + 5\) \(\large \sqrt{2^2 * 6^2} + 5\)

OpenStudy (boobear7411):

i am so confused

ganeshie8 (ganeshie8):

you need to put m = 36, in hte given expression and simplify

ganeshie8 (ganeshie8):

are you clear upto 2nd step above ?

OpenStudy (boobear7411):

yes

OpenStudy (boobear7411):

oh i get it now how you did the 2 thingy and the 6 thingy

ganeshie8 (ganeshie8):

lol yes, 2 thingy squared gives the 4 thingy

ganeshie8 (ganeshie8):

6 thingy squared gives the 36 thingy ;)

ganeshie8 (ganeshie8):

lets move on

ganeshie8 (ganeshie8):

square and radical cancel out

OpenStudy (boobear7411):

lol youre funny ♥

ganeshie8 (ganeshie8):

\(\large \sqrt{4m} + 5\) \(\large \sqrt{4 * 36} + 5\) \(\large \sqrt{2^2 * 6^2} + 5\) \(\large 2 * 6 + 5\) \(\large 2 * 6 + 5\) \(\large 12 + 5\) ?

OpenStudy (boobear7411):

17 ?

ganeshie8 (ganeshie8):

Yes !

OpenStudy (boobear7411):

thats the answer?

ganeshie8 (ganeshie8):

yes 17 is the answer. evaluate means, just finding the final value of the given expression.

OpenStudy (boobear7411):

Thank you ♥

ganeshie8 (ganeshie8):

u welcome =)

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