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1/4y-3=9 Help me!!plz!!! i got three but the answersheet says its 48
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\[\frac{ 1 }{ 4y-3 }=9\] \[4y-3=\frac{ 1 }{ 9 }\] \[4y=9+\frac{ 1 }{ 3 }=\frac{ 27+1 }{3}=\frac{ 28 }{ 3 },y=\frac{ 28 }{21 }=\frac{ 4 }{ 3 }\]
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