The allele for a widow’s peak has complete dominance over the allele for a straight hairline (w). What is the probability of two parents heterozygous for a widow’s peak (Ww) having an offspring with a widow’s peak?

75 percent

50 percent

0 percent

25 percent

Question

The allele for a widow’s peak has complete dominance over the allele for a straight hairline (w). What is the probability of two parents heterozygous for a widow’s peak (Ww) having an offspring with a widow’s peak?

 75 percent

 50 percent

 0 percent

 25 percent

anonymous · Answer

|dw:1369322355706:dw|


So 4 3 out of 4 places on the square have a capital W,so it is a 75% chance

thomaster · Answer

Always draw Punnett squares in these kind of problems.
The parents are heterozygous which means they both have the genotype Ww.
I see the punnett square is already drawn above this post :D
So 3/4 of the offspring has a widows peak. 3/4 is equal to 75%

(made this reply 2 days ago just before OS went down xD)

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