The three Math Idol judges have been eliminating contestants all day! The number of one-step equations and two-step equations who have been eliminated today is equal to 610! If four times the number of one-step equations minus twice the number of two-step equations is equal to 340, how many one-step equations auditioned today?

260

340

350

670

Question

The three Math Idol judges have been eliminating contestants all day! The number of one-step equations and two-step equations who have been eliminated today is equal to 610! If four times the number of one-step equations minus twice the number of two-step equations is equal to 340, how many one-step equations auditioned today?

260

340

350

670

abb0t · Answer

call the unknowns "x" and "y"
so if the total number of one and two-step equations was 610
then:
x + y = 610

anonymous · Answer

A.

ddcamp · Answer

let a = number of 1 step equations and b = number of 2 step equations
a + b = 610
4a - 2b = 340

solve for a

abb0t · Answer

let "x" = onestep. so if its 4x the number of one-step, then that's 4x and twice the two-step equations would be 2y.
4x-2y = 340
and so forth.

abb0t · Answer

now you have a system. can you solve for them now?

anonymous · Answer

so it is A?

abb0t · Answer

for "a" or "x" ? 
you should be able to see the answer :)

anonymous · Answer

YES! A is the answer!!

abb0t · Answer

lol

anonymous · Answer

thank you!

abb0t · Answer

Guess you didn't learn anything, coleman :(