Question

can anybody help me in week 10 hw and lab 10.plz

Answer 1

chek ur msgs

Answer 2

H10P1
r*u
q*v
p*w
s*t

Answer 3

H10P2
((j*w*C)*(R1+R2) - (w*w*L*C)+1)/(j*w*C)
inf
inf
(L*j*w)/((1-L*C*w^2)+(L/(R1+R2))*j*w)
0
0
((R1+(1/(j*w*C)))*(R2+j*w*L))/((R1+(1/(j*w*C)))+(R2+j*w*L))
R2
R1

Answer 4

H10P3
R2/((R1+R2-L*C*R1*w^2) + (R1*R2*C + L)*j*w)
-(R2 + L*j*w)/((L*C*w^2 - 1) - R2*C*j*w)
(1/(R1*w))*sqrt((R1-R2)/R2)
(1/w)*sqrt(R1*R2-R2^2)
1057.01
52.85

Answer 5

if last two answers doesn't work use this
Cmatch=(sqrt (R1/R2 -1)) / (w * R1)
Lmatch=((sqrt (R1/R2 -1)) * R2) / w

Answer 6

LAB 10 ???

Answer 7

Lab 10
1) 1/(R*C)
2) R/L
3) L
4)800e-6
5) C
6) 20e-9

For the last answer i have no idea how that works XD !

Answer 8

For last question we can use a RLC circuit with f1 = 1KHz and f2=1MHz
L=R/(f1*2*pi)
C=1/(f2*R*2*pi)

I would like to know how do you find:
4)800e-6
6) 20e-9
I tried with the same formula above but maybe i cannot find the right frequency!!!

Answer 9

Hey this is Lab 10 solution

Answer 10

WEEK 11??